第一種 ~~1/(1x2)+1/(2x3)+1/(3x4)
#include
float sum(float);
int main (void){
float n;
printf("\n 1/(1x2)+1/(2x3)+1/(3x4)+......+1/(n-1)n,n=?");
scanf("%f",&n);
printf("\n 1/(1x2)+1/(2x3)+1/(3x4)+......+1/(%.0fx%.0f)=%f",n-1,n,sum(n));
getch();
return 0;}
float sum (float m){
if (m==2) return 1.0/2.0;
else return sum(m-1)+1/((m-1)*m);}
第二種~1/3+1/5+1/7
#include
float sum(float);
int main (void){
float n;
printf("\n 1/3+1/5+1/7+......+1/n,n=?");
scanf("%f",&n);
printf("\n 1/3+1/5+1/7+......+1/%f=%f",n,sum(n));
getch();
return 0;}
float sum (float m){
if (m==3) return 1.0/3.0;
else return sum(m-2)+1/m;}
比大小並輸出最大的數字
#include
int f(int,int,int);
int main(void){
int a,b,c;
printf("\n a=? b=? c=?");
scanf("%d %d %d",&a,&b,&c);
printf("\n Max(%d %d %d) is %d",a,b,c,f(a,b,c));
system("pause");
return 0;}
int f(int x,int y,int z){
int w=z;
if(x>w)w=x;
if(y>w)w=y;
return w;}
比大小2(與上面結果會相同)
#include
void f(int,int,int);
int main(void){
int a,b,c;
printf("\n a=? b=? c=?");
scanf("%d %d %d",&a,&b,&c);
f(a,b,c);
system("pause");
return 0;} //f main
/*以上為主程式*/
void f(int x,int y,int z){
int w=z;
if(x>w) w=x;
if(y>w) w=y;
printf("Max(%d %d %d) is %d",x,y,z,w);}
// return w; } //f f
